use truncation instead of rounding down or rounding to the nearest value when numerical calculations exceed precision limits

This commit is contained in:
MaysWind
2025-09-09 20:46:51 +08:00
parent d4603a1892
commit 7e2e1a4ad3
13 changed files with 36 additions and 36 deletions
+4 -4
View File
@@ -230,7 +230,7 @@ export function formatNumber(value: number, options: NumberFormatOptions, precis
if (isDefined(precision)) {
const ratio = Math.pow(10, precision);
const normalizedValue = Math.floor(value * ratio);
const normalizedValue = Math.trunc(value * ratio);
const textualValue = numeralSystem.formatNumber(normalizedValue / ratio);
return appendDigitGroupingSymbolAndDecimalSeparator(textualValue, options);
} else {
@@ -242,7 +242,7 @@ export function formatNumber(value: number, options: NumberFormatOptions, precis
export function formatPercent(value: number, precision: number, lowPrecisionValue: string, options: NumberFormatOptions): string {
const numeralSystem = options.numeralSystem || NumeralSystem.Default;
const ratio = Math.pow(10, precision);
const normalizedValue = Math.floor(value * ratio);
const normalizedValue = Math.trunc(value * ratio);
if (value > 0 && normalizedValue < 1 && lowPrecisionValue) {
const systemDecimalSeparator = DecimalSeparator.Dot.symbol;
@@ -262,9 +262,9 @@ export function formatPercent(value: number, precision: number, lowPrecisionValu
export function getAmountWithDecimalNumberCount(amount: number, decimalNumberCount: number): number {
if (decimalNumberCount === 0) {
return Math.floor(amount / 100) * 100;
return Math.trunc(amount / 100) * 100;
} else if (decimalNumberCount === 1) {
return Math.floor(amount / 10) * 10;
return Math.trunc(amount / 10) * 10;
}
return amount;